The application solves a second order equation in the form
ax² + bx + c = 0 where a, b and c are real coefficients with a non-null.
The number of solutions of the equation depends on the discriminant:
- If Δ> 0, the equation has two real solutions denoted x1 and x2.
-> x1 = (-b - √Δ) / (2a)
-> x2 = (-b + √Δ) / (2a)
- If Δ = 0, then the equation has a double real solution denoted x0.
-> x0 = -b / (2a)
- If Δ <0, then the equation admits no real solution.
To solve the equation, I invite you to enter the values a, b and c as shown in the interface of the application, if your equation is in the form ax² + bX = 0 the value of C is 0 so you have entering 0 as c value and if in the form ax² + C = 0, the value of b is 0, thus 0 must be entered as the value of b.
I remain at your disposal for any additional information and thank you for contacting us to improve the application.
ax² + bx + c = 0 where a, b and c are real coefficients with a non-null.
The number of solutions of the equation depends on the discriminant:
- If Δ> 0, the equation has two real solutions denoted x1 and x2.
-> x1 = (-b - √Δ) / (2a)
-> x2 = (-b + √Δ) / (2a)
- If Δ = 0, then the equation has a double real solution denoted x0.
-> x0 = -b / (2a)
- If Δ <0, then the equation admits no real solution.
To solve the equation, I invite you to enter the values a, b and c as shown in the interface of the application, if your equation is in the form ax² + bX = 0 the value of C is 0 so you have entering 0 as c value and if in the form ax² + C = 0, the value of b is 0, thus 0 must be entered as the value of b.
I remain at your disposal for any additional information and thank you for contacting us to improve the application.
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